Member since Oct 2014
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20191118, 15:55 #1
Subject: Assignment 4.2, Problem 3  Evaluation function
There seems to be no definition to which value X_2, X_1, O_2 and O_1 evaluate. Does that mean that we are supposed to write answers unresolved, e.g. for s=[[X, _, _], [_, O, _], [_, _, _]], Eval(s)=2X_1(s)3O_1(s)?
Or are we supposed to assume theses cases evaluate to the same values as X_3 (+1) respectively O_3 (1)? In this case the evaluation function would not always valuate a terminal winning state higher than another state: For s=[[X,_,O], [_,X, X], [_,O,O]] and (obviously) X's turn, there are three possible successor states:  s_1=[[X,X,O], [_,X, X], [_,O,O]]  s_2=[[X,_,O], [X,X, X], [_,O,O]]  s_3=[[X,_,O], [X,X, X], [_,O,O]] Where s_2 is the best state, because it is a terminal state that wins the game for X. Eval(s_i) is therefor:  i=1: 3X_2(s)+X_1(s)3O_2(s)=3+13=+1  i=2: X_3(s)=+1  i=3: 6X_2(s)=+6 => This state would be chosen, when maximizing (=X is trying to win). The followup state of s_3 would be a draw (if O is minimizing), resulting in an worse result, than when choosing the winning terminal state s_2. 
Member for 2 months
54 posts

20191119, 10:13 #2
With the evaluation function, the idea is just to evaluate the nodes at depth 2. The definition of X_2, X_1, etc is in the first paragraph of the problem:
For example, the state [[X, _, _], [_, O, _], [_, _, _]] has  X_2 = 0 (because there are no rows, columns or diagonals with only two Xs)  X_1 = 2 (there is one row and one column with exactly one X, and no diagonals, since the diagonal also includes O)  O_2 = 0 (because there are no rows, columns or diagonals with two Os)  O_1 = 3 (there is one row and one column with exactly one O, as well as one diagonal) Does this help? 
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